KeyGenMe #5 :: .NET :: Difficulty : 4 [HARD !]

KeyGenMe Location : KeyGenMe #5 @ Crackmes.de
Solution Location : Solution by indomit.

One of my hardest KeyGenMes yet !! KeyGenMe #5. It's coded in VB.NET. Features :
(*) NOT Packed
(*) NOT Encrypted
(*) Kool GFX

The Rules :
(*) NO Patching
(*) NO Brute-forcing

The Tasks :
1. Try to get Status as "VALID".
2. Find the algorithm for the computations involved.
3. Make keygen to VALID Key for ANY name. Please note that VALID KEYS EXIST FOR ALL NAMES.
4. Write a descent tutorial. ;)

The Hint :
==========---
Think about MID(KEY,2,3) where KEY is ANY VALID KEY. ;-)

Readers, if you solve this, please upload your solution to CrackMes.de.

KeyGenMe #2 Ver.2.00 :: C++ :: Difficulty : 3

KeyGenMe Location : KeyGenMe #2 Ver.2.00 @ Crackmes.de
Solution Location : Solution by obnoxious

My second version of KeyGenMe #2. It's coded in GNU C++. Features :
(*) NOT Packed
(*) NOT Encrypted
(*) C00L console look.

The Rules :
(*) NO Patching
(*) NO Brute-forcing

The Tasks :
1. Find a correct combination of RefID and License-Key.
2. Find the algorithm for Key and RefID calculations
3. Make a KEYGEN.
4. Write a descent tutorial. ;)

Readers, if you solve this [in a different method than obnoxious], please upload your solution to CrackMes.de.

KeyGenMe #2 :: C++ :: Difficulty : 3

KeyGenMe Location : KeyGenMe #2 @ Crackmes.de
Solution Location : Solution by obnoxious


My second version of KeyGenMe #2. It's coded in GNU C++. Features :
(*) NOT Packed
(*) NOT Encrypted
(*) C00L console look.

The Rules :
(*) NO Patching
(*) NO Brute-forcing

The Tasks :
1. Find a correct combination of RefID and License-Key.
2. Find the algorithm for Key and RefID calculations
3. Make a KEYGEN.
4. Write a descent tutorial. ;)

The Hints :
1. The serial can consists of the entire array of visible chracters, but
only 4 different characters would also be enough.
2. THE 4 different characters are ( 2 * Alphabets ) + ( 2 * Numbers )
3. ANY set of 4 different [ even though they too may be ( 2 * Alphabets )
+ ( 2 * Numbers ) ] characters won't work.
There exists ONLY 1 such set.
4. Most important HINT : Idea of this is inspired by bRaInF**k.

Readers, if you solve this [in a different method than obnoxious], please upload your solution to CrackMes.de.